Equation Icon  Ti(1j,1)(𝔥) = Rij, (1,2) 1- klm Tij (𝔥) = 4Riklm Rj , (B.64 ) T (1,3)(𝔥) = 1R kR Rpnmq − 1R Rk Rlmnp − -1-∇ R ∇kR lmn, ij 6 imn jpqk 8 iklj mnp 12 n iklm j