Equation Icon  ττ 6 ∑ rkA- k 8 ∑ rkArlA- kl h = 4ε r3D A + 6ε r5 IA A=1,2 A A=1,2 A ∑ rk ∑ rkrl ∑ rk = 4ε6 -A3dkA + 6ε8 -A5A-IkAl+ 4ε8 -A3M AkiviA + 𝒪 (ε9), (217 ) A=1,2 rA A=1,2 rA A=1,2 rA ∑ rk 6h τi = 2 -AM kAi , (218 ) A=1,2r3A ∑ k hij = 4 rAM k(ivj). (219 ) 6 r3A A A A=1,2 i 42m2M--1ik k Q1 = ε 3r3 r12. (220 ) 12