Equation Icon  ∑ ( τ k k ⟨kl⟩ k l ⟨klm⟩ k l m ) hττ = 4ε4 P-A + ε2D-ArA-+ ε4 3IA--rArA-+ ε65IA----rArArA- + 𝒪 (ε12), (78 ) B n=0 A=1,2 rA r3A 2r5A 2r7A ( i ki k kli k l ) τi 4∑ P-A 2JA-rA- 43J-A-rArA- 10 hB n=0 = 4ε rA + ε r3A + ε 2r5A + 𝒪 (ε ), (79 ) A=1,2( ) ∑ Zij Zkijrk 3Z ⟨kl⟩ijrkrl 5Z ⟨klm ⟩ijrkrlrm hiBjn=0 = 4ε2 --A-+ ε2--A-3A-+ ε4--A---5-A-A-+ ε6---A-----7A-A-A- + 𝒪(ε10). (80 ) A=1,2 rA rA 2rA 2rA