Equation Icon  [h, Ebicd] = − 1[(Kcc + Kdd ),Ebicd] + 2-[(Kb1b + Kb2b + Kb3b ),Ebicd] ( 3 ) 3 1 2 3 1- 1- 2- bicd = − 3 − 3 + 3 E = 0 (i = 1,2,3). (10.51 )