Equation Icon  [ ] ∑10 ds2 = − e14&tidle;φ+2φ∕3dt2 + e4φ∕3 (dx1 )2 + (dx2 )2 + (dx3)2 + e2&tidle;φ−2φ∕3 (dx¯a)2 ¯a=4 √ -- √-- 10 1∕3 13 &tidle;Et 2 −2∕3 [ 12 2 2 3 2] 1∕3 2&tidle;E1 t∑ ¯a 2 = − H (t)e dt + H (t) (dx ) + (dx ) + (dx ) + H (t)e (dx ) , ¯a=4 (10.45 )