Equation Icon  š’œa a a b1⋅⋅⋅bk(t) = ∂b1 ⋅⋅⋅∂bkš’œa aa (t), 12 2b1⋅⋅⋅bk b1 b 12 3 š’œa1 ⋅⋅⋅a6 (t) = ∂ ⋅⋅⋅∂ kš’œa1 ⋅⋅⋅a6(t), (9.150 ) š’œa |a ⋅⋅⋅a b1⋅⋅⋅bk(t) = ∂b1 ⋅⋅⋅∂bkš’œa |a ⋅⋅⋅a (t). 1 2 9 1 2 9