Equation Icon  1 ( ) n(t)−1 ( 1 ) --∂ n(t)− 1gac(t)∂gcb(t) = ------- 𝒟 𝒜ac1c2(t)𝒟 𝒜bc1c2(t) − -δab𝒟 𝒜c1c2c3(t)𝒟 𝒜c1c2c3(t) 2 4 9 n(t)−1( 1 ) + ------- 𝒟 𝒜ac1⋅⋅⋅c5(t)𝒟 𝒜bc1⋅⋅⋅c5(t) − --δab𝒟 𝒜c1 ⋅⋅⋅c6(t) 𝒟𝒜c1 ⋅⋅⋅c6(t) , 2 ⋅ 5! 9 (9.139 ) − 1 a1a2a3 1- −1 a1⋅⋅⋅a6 ∂ (n(t) 𝒟 𝒜 (t)) = − 3! n(t) 𝒟 𝒜 (t) 𝒟𝒜a4a5a6(t), −1 a⋅⋅⋅a ∂ (n(t) 𝒟 𝒜 1 6(t)) = 0.