Equation Icon  √ --- ds2 = − (H H H H )1∕3e23 E−tdt2 + (H H )−2∕3(H H )1∕3(dx1)2 (62,43) 1 2 3 4 1 4 2 3 +(H1H3 )−2∕3(H2H4 )1∕3(dx2)2 + (H1H2 )− 2∕3(H3H4 )1∕3(dx3)2 −2∕3 1∕3 42 − 2∕3 1∕3 5 2 +(H3H4 ) (H1H2 ) (dx ) + (H2H4 ) (H1H3 ) (dx ) 1√--- ∑10 +(H2H3 )−2∕3(H1H4 )1∕3(dx6)2 + (H1H2H3H4 )1∕3e 6 E −t (dx¯a)2. (10.59 ) ¯a=7