Equation Icon  β,r = -1-rhAC hBD hAB,r hCD,r, (24 ) ( ) 16 ( ) r4e− 2βhABU B,r = 2r4 r −2β,A − r2hBC DC (hAB,r) (25 ) ,r ,r (( ) ) 2e−2βV,r = ℛ − 2DADA β − 2 (DA β)DA β + r− 2e− 2βDA r4U A ,r 1-4 − 4β A B − 2r e hAB U,r U ,r, (26 )