Equation Icon  β = -1-rhAC hBD h h , (36 ) ,r 16 AB,r CD,r (r4e− 2βh U B ) = 2r4(r −2β ) − r2hBC D (h ) (37 ) AB ,r ,r ,A ,r C AB,r ( ) 2e−2βV = ℛ − 2DAD β − 2 (DA β)D β + r− 2e− 2βD (r4U A) ,r A A A ,r 1-4 − 4β A B − 2r e hAB U,r U ,r, (38 )