Equation Icon  [ ] ℱ (⃗k1,⃗k2) b2(z) B (⃗k1,⃗k2,⃗k3,z) = 2P (k1)P (k2 )b1(z)3 × fNL ---------+ J(⃗k1,⃗k2) + ------ + cyc. (3.4.5 ) D (z) 2b1(z) (3.4.6 )